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Post by zadow on Jun 16, 2009 4:17:10 GMT -8
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Post by black_dragonet on Jun 16, 2009 4:41:39 GMT -8
I liked that one: Classy enough to make a decent vampire. The blonde I didn't even find attractive.
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rel
New Member
byrren jous ninta yibinss wun ninta xo'a ulu kl'ae vel'bol zhah udosst..er'griff l' seke ph' shebali
Posts: 1,013
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Post by rel on Jun 16, 2009 5:36:40 GMT -8
listen to what you just said.... say it out loud *grins* she's outside on a beach and she's classy enough to make a decent vampyre? I LOVE THAT STATEMENT!
What in the world does that mean? I WANNA KNOW WHAT THAT MEANS! oh THANK you for making me smile this morning. I hug you thru the computer.
oh - and you're totally spot on - that blonde...dunno just no... SECOND REDHEAD? the pin up? She's awesome. someone should use her...
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Vera
New Member
Posts: 666
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Post by Vera on Jun 16, 2009 6:36:21 GMT -8
There's this thing called cropping and erasing which means she doesn't have to be on a beach. Baffling, I know.
Anyway, I have loads of models stored up. I'll make up a list and post it here soon. >.>
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rel
New Member
byrren jous ninta yibinss wun ninta xo'a ulu kl'ae vel'bol zhah udosst..er'griff l' seke ph' shebali
Posts: 1,013
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Post by rel on Jun 16, 2009 7:26:59 GMT -8
Of course i know that - *blinks* it's still hilarious...
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Post by ophelia Lokason on Jun 16, 2009 7:28:51 GMT -8
I think redheads are the hardest to find. At least for me when dealing with opie ><
The ones liked are beautiful but a bit to...unclothed or over the top for my tastes.
~M
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Vera
New Member
Posts: 666
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Post by Vera on Jun 16, 2009 8:48:00 GMT -8
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Promethius
New Member
[modified for insult][C01:0000DD]
Posts: 308
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Post by Promethius on Jun 16, 2009 12:27:42 GMT -8
I'll say what I've been saying for years now: SOMEONE USE KYLA COLE. Yeah, she's a porn star, but good lord she's the most beautiful model ever. And there ARE good pictures of her with clothes on. * A whole gallery of Kyla (nudity cropped out)Also, someone could probably use Billie Piper: Also, it's not strange there's sexy redheads. Redheads are rawr.
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Liander
New Member
Lead me, follow me, or get out of my way.
Posts: 430
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Post by Liander on Jun 16, 2009 12:30:59 GMT -8
I just want to ask... What about male models?
It took me hours to finally settle on Jensen Ackles on Liander, but I'm still not 100% on that choice.
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Post by Luce Scura on Jun 16, 2009 13:33:18 GMT -8
rel said: SECOND REDHEAD? the pin up? She's awesome. someone should use her... Ok, I'm going to go out on a limb here and guess ......... someone probably has used her ............ ~evil grin~
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rel
New Member
byrren jous ninta yibinss wun ninta xo'a ulu kl'ae vel'bol zhah udosst..er'griff l' seke ph' shebali
Posts: 1,013
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Post by rel on Jun 16, 2009 13:43:01 GMT -8
rel said: SECOND REDHEAD? the pin up? She's awesome. someone should use her... Ok, I'm going to go out on a limb here and guess ......... someone probably has used her ............ ~evil grin~ HAHAHAHA - oh and Billie Piper? WHAT A FANTASTIC IDEA!
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◞◯◟
New Member
IGN: upir
Posts: 759
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Post by ◞◯◟ on Jun 16, 2009 16:07:41 GMT -8
I think more people should go to Model Mayhem. Celebrities, actors, and musicians are just... eh.
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Post by Katastrophe St. John-Talon on Jun 16, 2009 16:45:39 GMT -8
I didn't know about Model Mayhem back when I picked Ali.
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Post by Lestat de Lioncourt on Jun 16, 2009 16:47:40 GMT -8
Deviant art gets you more of those diamonds in the rough.
I'll stick with my unknown actor that looks more like Lestat than both actors combined, though.
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Post by Nephriel B. R. de laFronde on Jun 16, 2009 17:22:04 GMT -8
I just want to ask... What about male models? It took me hours to finally settle on Jensen Ackles on Liander, but I'm still not 100% on that choice. Male models are so hard to find >.o I spent ages trying to find a good model for Nephriel and I still have yet to succeed. I guess it's the fact that he's got a porcelain complexion and almost white hair? His eyes are completely white too but I usually photoshop them for that. I dunno but I'd appreciate some help finding a model if anyone wants to take up this request. x.x
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